-16x^2+50x+5=0

Solution for -16x^2+50x+5=0 equation:

-16x^2+50x+5=0

a = -16; b = 50; c = +5;
Δ = b2-4ac
Δ = 502-4·(-16)·5
Δ = 2820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2820}=\sqrt{4*705}=\sqrt{4}*\sqrt{705}=2\sqrt{705}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{705}}{2*-16}=\frac{-50-2\sqrt{705}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{705}}{2*-16}=\frac{-50+2\sqrt{705}}{-32}
$